In a double slit experiment, the separation between the slits is d and distance of the screen from slits is D. If the wavelength of light used is `lambda` and I is theintensity of central bright fringe, then intensity at distance from central maximum is

Options

A. `I cos^(2) ((pi^(2)xd)/(lambda D))`
B. `I^(2)sin^(2) ((pi xd)/(2 lambda D))`
C. `I cos^(2) ((pi xd)/(lambda D))`
D. `I sin^(2) ((pi xd)/(lambda D))`

Answer

C

Explanation

`I = I_(0)cos^(2) ((theta)/(2))`