In YDSE shown in figure a parallel beam of light is incident on the slits from a medium of refractive index `n_(1)`. The wavelength of light in this medium is `lambda_(1)`. A transparent of thickness t and refractive index `n_(3)` is put in front of one slit. The medium between the screen and the plane of the slits is `n_(2)`. The phase difference between the light waves reaching point O (symmetrical, relative to the slits) is

Options

A. `(2pi)/(n_(1)lambda_(1))(n_(3) - n_(2))t`
B. `(2pi)/(lambda_(1))(n_(3) - n_(2))t`
C. `(2pi n_(1))/(n_(2)lambda_(1)) ((n_(3))/(n_(2))- 1)t`
D. `(2pi n_(1))/(lambda_(1))(n_(3) - n_(2))t`

Answer

A

Explanation

Optical path difference between the waves `=(n_(3) - n_(2))t`
Phase difference `= 2 lambda (n_(3) - n_(2))t , (2pi(n_(3) - n_(2))t)/(n_(1)lambda)`