If `I_0` is the intensity of the principal maximum in the single slit diffraction pattern. Then what will be its intensity when the slit width is doubled?

Options

A. `I_(0)`
B. `I_(0)//2`
C. `(1)/(2)I_(0)`
D. `4I_(0)`

Answer

A

Explanation

`I = I_(0)((sin phi)/(phi))^(2)` Where `phi` is path difference for principal maxima, `phi = 0` Hence, intensity will remain same `(= I_(0))` Increaseing the width of the slit will make the central peak more narrow.