A polariser and an analyser are oriented so that the maximum amount of lights is transmmitted. Fraction of its maximum value is the intensity of the transmitted through reduced when the analyzer is rotated through (intensity of incident light `= I_(o)`) , a) `30^(@)` , b) `45^(@)` , c) `60^(@)`

Options

A. `0.375 I_(0), 0.25I_(0), 0.125 I_(0)`
B. `0.25 I_(0), 0.375 I_(0), 0.125 I_(0)`
C. `0.125 I_(0), 0.25 I_(0), 0.0375 I_(0)`
D. `0.125 I_(0), 0.375 I_(0) , 0.25 I_(0)`

Answer

A

Explanation

`I = (I_(0))/(2) cos^(2) theta`