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The arrangement for a mirror experiment ...

The arrangement for a mirror experiment is shown in figure. S is a point source of frequency `6xx10^(14)Hz`. D and C represent the two ends of a mirror placed horizontally and LOM represents the screen.

Find the fringe width of the fringe pattern ?

A

`0.05cm`

B

`0.25cm`

C

`0.01cm`

D

`0.1cm`

Text Solution

Verified by Experts

The correct Answer is:
A
Wavelength of light used is
`lambda = (C )/(D) = (3xx10^(8))/(6xx10^(14)) = 5xx10^(-7)m`
Fringe width `(beta) = (lambda D)/(d)`
`D = S_(1)A = 200 cm = 2m` ,
`d = SS_(1) = 2mm = 2xx10^(-3)m`
`beta = (5xx10^(-7)xx2)/(2xx10^(-3)) = 5xx10^(-4)m`
`beta = 5xx10^(-2) cm implies beta = 0.05 cm`
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