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In Young's double slit experiment, the 1...

In Young's double slit experiment, the 10th maximum of wavelength `lambda_(1)` is at distance of `y_(1)` from the central maximum. When the wavelength of the source is changed to `lambda_(2)` , 5th maximum is at a distance of `y_(2)` from its central masximum. Then `(y_(1))/(y_(2))` is

A

`(2lambda_(1))/(lambda_(2))`

B

`(2lambda_(2))/(lambda_(1))`

C

`(lambda_(1))/(2lambda_(2))`

D

`(lambda_(2))/(2lambda_(1))`

Text Solution

Verified by Experts

The correct Answer is:
A
`y_(2) = 5 ((lambda_(2)D)/(d)) , y_(1) = 10((lambda_(1)D)/(d))`
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