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A plane wave of wavelength 6250 Å is inc...

A plane wave of wavelength `6250 Å` is incident normally of the principal maximum on a screen distant 50 cm will be

A

`312.5 xx 10^(-2)cm`

B

`312.5xx10^(-4)cm`

C

`312cm`

D

`312.5xx10^(-5)cm`

Text Solution

Verified by Experts

The correct Answer is:
A
Here, `lambda = 6250 Å = 6520 x 10^(-10)m`
`a = 2xx10^(-2)cm = 2xx10^(-4)m`
`D = 50 cm = 0.5 m`
`:.` Width of central maxima `= (2lambda D)/(a)`
`= (2xx6250xx10^(-10)xx0.5)/(2xx10^(-4)) = 312.5xx10^(-3) cm`
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