Calculate the percent ionization of `0.10M` acetic acid `(K_a=1.8xx10^(-5))`.

Explanation

To calculate the percent ionization of 0.10 M acetic acid (CH₃COOH) with a dissociation constant \( K_a = 1.8 \times 10^{-5} \), we can follow these steps:

### Step 1: Write the dissociation equation
The dissociation of acetic acid in water can be represented as:
\[ \text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+ \]

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