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If for heterogeneous equilibrium, CaCO...

If for heterogeneous equilibrium,
`CaCO_3(s)hArr CaO(s)+CO_2(g), K_(eq)=1` at `1 atm`
pressure, the corresponding temperature is given by

A

`T=(DeltaG^(Θ))/(DeltaH^(Θ))`

B

`T=(DeltaG^(Θ))/(R)`

C

`T=(DeltaS^(Θ))/(DeltaH)`

D

`T=(DeltaH^(Θ))/(DeltaS^(Θ))`

Text Solution

Verified by Experts

The correct Answer is:
D
According to thermodynamics
`DeltaG^(Θ)=DeltaH^(Θ)-TDeltaS^(Θ)`
At equilibrium, `DeltaG^(Θ)=0`. Thus,
`0=DeltaH^(Θ)-TDeltaS^(Θ)`
`DeltaH^(Θ)=TDeltaS^(Θ)`
`T=DeltaH^(Θ)//DeltaS^(Θ)`
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