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The units of solubility product of silve...

The units of solubility product of silver chromate `(AgCrO_(4))` will be

A

`mol^(2)L^(-2)`

B

`mol^(3)L^(-3)`

C

`mol L^(-1)`

D

`mol^(-1)L`

Text Solution

Verified by Experts

The correct Answer is:
B
The solubility product is an equilibrium constant.
`Ag_(2)CrO_(4)(s)hArr2Ag^(+)(aq.)+CrO_(4)^(2-)(aq.)`
`K_(sp) = C_(Ag^(+))^(2)C_(CrO_(4)^(2-))`
`= (mol L^(-1))^(2)(mol L^(-1))= mol^(3)L^(-3)`
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