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Given K(sp)(AgI)=8.5xx10^(-17). The solu...

Given `K_(sp)(AgI)=8.5xx10^(-17)`. The solubility of AgI in `0.1M KI` solution is

A

`0.1M`

B

`8.5xx10^(-16)M`

C

`8.5xx10^(-17)M`

D

`8.5xx10^(-18)M`

Text Solution

Verified by Experts

The correct Answer is:
B
Since KI is a soluble strong electrolyte, it dissociates completely:
`KI(s)overset(H_(2)O)rarrK^(+)(aq.)+I^(-)(aq.)`
`0.1M " " 0.1M`
Let S be the molar solubility of AgI in KI solution:
`{:(,AgI(g)(s)hArrAg^(+)(aq.)+I^(-)(aq.)),("Initial (M)"," 0.0 0.1"),("Change (M)"," +S +S"),("Equilibrium (M)",bar(" S (0.1+S)")):}`
`K_(sp)= C_(Ag^(+))C_(I^(-))`
`8.5xx10^(-17) =(S)(0.1+S)`
Since AgI is quite insoluble and the presence of `I^(-)` from `KI` further lowers the solubility of AgI (due to common ion effect), S must be very small compared with `0.1`, we obtain
`8.5xx10^(-17)=(S)(0.1)`
`S= (8.5xx10^(-17))/(0.1)`
`=8.5xx10^(-16)`
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