The ionization constant of ammonium hydroxide is `1.77xx10^(-5)` at `298 K`. Hydrolysis constant of ammonium chloride is

Options

A. `6.50xx10^(-12)`
B. `5.65xx10^(-13)`
C. `5.65xx10^(-12)`
D. `5.65xx10^(-10)`

Answer

D

Explanation

`NH_(4)Cl` is the salt of weak of `OH^(-)` ions. Acid (HCI). For such a salt, we have
`K_(h)=(K_(w))/(K_(b))=(1xx10^(-14))/(1.77xx10^(-5))`
`=0.565xx10^(-9)`
`=5.65xx10^(-10)`