If the concentration of `OH^(-)` ions in the reaction
`Fe(OH)_(3)(s)hArrFe^(3+)(aq.)+3OH^(-)(aq.)`
is decreased by `1//4` times, then the equilibrium concentration of `Fe^(3+)` will increase by

Options

A. 8 times
B. 16 times
C. 64 times
D. 4 times

Explanation

To solve the problem, we will follow these steps:

### Step 1: Write the equilibrium expression
For the reaction:
\[ \text{Fe(OH)}_3(s) \rightleftharpoons \text{Fe}^{3+}(aq) + 3 \text{OH}^-(aq) \]

The equilibrium constant \( K \) can be expressed as:
\[ K = \frac{[\text{Fe}^{3+}]}{[\text{OH}^-]^3} \]
...