When phenol is heated with `CHCl_(3)` and alcoholic `KOH`, salicylaldehyde is produce. This reaction is known as

Options

A. Rosenumud's reaction
B. Reimer - Tiemann reaction
C. Friedel - Craft's reaction
D. Sommelet reaction

Explanation

To determine the name of the reaction when phenol is heated with chloroform (CHCl3) and alcoholic KOH, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are phenol (C6H5OH), chloroform (CHCl3), and alcoholic potassium hydroxide (KOH).

2. **Understand the Reaction Conditions**: The reaction takes place under heating conditions, which is essential for the reaction to proceed.

3. **Recognize the Product**: The product formed from this reaction is salicylaldehyde (C7H6O), which is a compound with a hydroxyl group (-OH) and an aldehyde group (-CHO) on adjacent carbon atoms.

4. **Recall the Type of Reaction**: The reaction between phenol and chloroform in the presence of a strong base (like alcoholic KOH) is a specific type of reaction in organic chemistry.

5. **Name the Reaction**: This reaction is known as the **Reimer-Tiemann reaction**. It is a well-known reaction that involves the ortho-formylation of phenols.

6. **Conclusion**: Therefore, when phenol is heated with CHCl3 and alcoholic KOH, salicylaldehyde is produced, and this reaction is called the Reimer-Tiemann reaction.

### Final Answer:
The reaction is known as the **Reimer-Tiemann reaction**.

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