The `IUPAC` name of `CH_(3)OCH_(2)CH_(2)OCH_(2)CH_(2)OCH_(2)CH_(3)` is

Options

A. `3,6,9-`trioxadecane
B. ethoxy methoxy diethyl ether
C. ethoxymethyl methoxyethyl ether
D. `2,5,8-`trioxdecane

Explanation

To determine the IUPAC name of the compound `CH3OCH2CH2OCH2CH2OCH2CH3`, we will follow these steps:

### Step 1: Identify the longest carbon chain
The first step in naming the compound is to identify the longest continuous carbon chain. In this case, the longest chain consists of 10 carbon atoms, which can be represented as:

- CH3 (1 carbon)
- O (1 oxygen)
- CH2 (2 carbon)
- O (1 oxygen)
- CH2 (2 carbon)
- O (1 oxygen)
- CH2 (2 carbon)

This gives us a total of 10 carbon atoms.

### Step 2: Determine the base name
The base name for a straight-chain alkane with 10 carbon atoms is "decane."

### Step 3: Count and position the oxygen atoms
Next, we need to count the number of oxygen atoms in the chain. There are 3 oxygen atoms in total. We will also need to determine their positions in the carbon chain:

- The first oxygen is at position 2 (between the first and second carbon).
- The second oxygen is at position 5 (between the fourth and fifth carbon).
- The third oxygen is at position 8 (between the seventh and eighth carbon).

### Step 4: Use the OXA nomenclature
According to the OXA nomenclature, we will use the prefix "oxa" for each oxygen atom. Since there are three oxygen atoms, we will use the prefix "tri-" to indicate three occurrences of the "oxa" prefix.

### Step 5: Combine the information
Now we can combine all the information to create the full IUPAC name:

- The positions of the oxygen atoms are 2, 5, and 8.
- The prefix for three oxygen atoms is "tri-."
- The base name is "decane."

Putting it all together, the IUPAC name of the compound is:

**2, 5, 8-tri-oxa-decane**

### Final Answer:
The IUPAC name of `CH3OCH2CH2OCH2CH2OCH2CH3` is **2, 5, 8-tri-oxa-decane**.

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