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In the following reaction: H(3)C-under...

In the following reaction:
`H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C )-CH=CH_(2)overset(H_(2)O //H6(+))(rarr)underset("product")underset("Major")(A)+underset("Product")underset("Minor")(B)`
The major product is

A

`H_(3)C-overset(CH_(3))overset(|)underset(OH)underset(|)(C)-underset(CH_(3))underset("| " )(CH)-CH_(3)`

B

`underset(OH)underset("| ")(CH_(2))-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C) -CH_(2) -CH_(3)`

C

`H_(3)C-overset(CH_(3))overset(|)underset(H_(3)C)underset(|)(C)-underset(OH)underset("| ")(CH) -CH_(3)`

D

`H_(3)C-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C)-CH_(2)-underset(OH)underset(|)(CH_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
The major product is formed from relatively more stable rearranged carbocation:
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