It `100 mL` of `0.6 N H_(2)SO_(4)` and `200 mL` of `0.3 N HCl` are mixed together, the normality of the resulting solution will be

Options

A. `3/5`
B. `1/5`
C. `2/5`
D. `5/3`

Answer

3

Explanation

If two different solutions of non-reacting substances are mixed then the resulting normality or molarity is given as
Normality `(N)=(("Total number of meq or eq"),((N_(1)V_(1)+N_(2)V_(2))))/(("Total volume of solution" (V_(1)+V_(2))),(in mL or L))`
`"Molarity" (M)=(("Total number of millimoles or"),("moles" (M_(1)V_(1)+M_(2)V_(2))))/(("Total volume of solution" (V_(1)+V_(2)))`, (i n mL or L))
meg of `H_(2)SO_(4) =V_(mL)xxN`
`=(100)(0.6)=60`
meq of `HCl=V_(mL)xxN`
`=(200)(0.3)=60`
Thus, normality of the resulting solution
`N=("Total meq')/("Total mL")=((60+60) meq)/((100+200) mL)`
`=(120 meq)/(300 mL)`
`=2/5 N`