A sample of `Na_(2)CO_(3).H_(2)O` weighing `0.62 g` is added to `100 mL` of `0.1 N H_(2)SO_(4)`. The resulting solution will be

Options

A. acidic
B. basic
C. amphoteric
D. neutral

Explanation

To determine the nature of the resulting solution when `Na2CO3.H2O` is added to `0.1 N H2SO4`, we can follow these steps:

### Step 1: Calculate the equivalent weight of `Na2CO3.H2O`
The formula for equivalent weight is given by:

\[ \text{Equivalent Weight} = \frac{\text{Molar Mass}}{n} \]

Where \( n \) is the total positive charge contributed by the solute.

1. **Calculate the molar mass of `Na2CO3.H2O`:**
- Sodium (Na) = 23 g/mol, Carbon (C) = 12 g/mol, Oxygen (O) = 16 g/mol, Water (H2O) = 18 g/mol.
- Molar mass of `Na2CO3` = \( 2 \times 23 + 12 + 3 \times 16 = 46 + 12 + 48 = 106 \) g/mol.
- Molar mass of `H2O` = 18 g/mol.
- Total molar mass of `Na2CO3.H2O` = \( 106 + 18 = 124 \) g/mol.

2. **Determine the total positive charge:**
- `Na2CO3` contributes 2 Na⁺ ions, so \( n = 2 \).

3. **Calculate the equivalent weight:**
\[ \text{Equivalent Weight} = \frac{124 \text{ g/mol}}{2} = 62 \text{ g/equiv} \]

### Step 2: Calculate the number of equivalents of `Na2CO3.H2O`
Using the formula:

\[ \text{Number of Equivalents} = \frac{\text{Given Mass}}{\text{Equivalent Weight}} \]

Given mass = 0.62 g.

\[ \text{Number of Equivalents} = \frac{0.62 \text{ g}}{62 \text{ g/equiv}} = 0.01 \text{ equiv} \]

### Step 3: Convert equivalents to milli-equivalents
To convert to milli-equivalents:

\[ \text{Milli-Equivalents} = \text{Number of Equivalents} \times 1000 \]

\[ \text{Milli-Equivalents} = 0.01 \times 1000 = 10 \text{ mEq} \]

### Step 4: Calculate the milli-equivalents of `H2SO4`
Using the formula:

\[ \text{Milli-Equivalents} = \text{Volume (mL)} \times \text{Normality} \]

Given volume = 100 mL and normality = 0.1 N:

\[ \text{Milli-Equivalents of H2SO4} = 100 \text{ mL} \times 0.1 \text{ N} = 10 \text{ mEq} \]

### Step 5: Compare the milli-equivalents
Since the milli-equivalents of `Na2CO3.H2O` (10 mEq) is equal to the milli-equivalents of `H2SO4` (10 mEq), they will neutralize each other.

### Step 6: Determine the resulting solution
The reaction between `Na2CO3` and `H2SO4` produces `Na2SO4` and water:

\[ \text{Na2CO3} + \text{H2SO4} \rightarrow \text{Na2SO4} + \text{H2O} + \text{CO2} \]

Since `Na2SO4` is a neutral salt and does not hydrolyze in water, the resulting solution will be neutral.

### Final Answer
The resulting solution will be **neutral**.

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