Home
Class 12
CHEMISTRY
The vapor pressure 'P' in mmHg of a bina...

The vapor pressure 'P' in mmHg of a binary solution of two volatile components `A` and `B` at a certain temperature is represented by the equation
`P=245-101 chi`
where `chi` is the mole fraction of component A. The vapor pressures of the pure components `A` and `B` are____ respectively

A

`245 mmHg, 144 mmHg`

B

`144 mmHg, 245 mmHg`

C

`346 mmHg, 144 mmHg`

D

`144 mmHg, 346 mmHg`

Text Solution

Verified by Experts

The correct Answer is:
2
Consider the equation
`P=245-101 chi`
When `chi=1`, the system has only pure component `A`. Thus `P=P_(A)^(@)=245-101=144 mmHg`. On the component `B`. Thus, `P=P_(B)^(@)=245 mmHg`. Alternatively, we can compare the given equation with `P=P_(B)^(@)+(P_(A)^(@)-P_(B)^(@))xhi_(A)` to get the answer.
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

At a given temperature, the vapour pressure in mm of Hg. of a solution of two volatile liquids A and B is given by the equation : rho = 120-80 X_(B) , X_(B) = mole fraction of B. Vapour pressures of pure A and B at the same temperature are respectively

An ideal binary solution of two volatile compenents A and B are in equilibrium with atmospheric pressure at T kelvin. Find (P_(A)^(@)+P_(B)^(@)) in atmosphere if the mole fraction of more volatille component in solution is (1)/(2) .

P_(A)and P_(B) are the vapour pressure of pure liquid components ,Aand B respectively of an ideal binary solution,If x_(A) represents the mole fraction of component A, the total pressure of the solution will be

Mixture of volatile components A and B has total pressure ( in Torr ) p=265-130x_(A), where X_(A) is mole fraction of A in mixture . Hence P_(A)^(@)+P_(B)^(@)= ( in T o r r).