Molal freezing point depression constant `(K_(f))` may be calculated from the following thermodynamically derived equation

Options

A. `K_(f)=(RT_(f)^(2) DeltaH_(fus))/1000`
B. `K_(f)=(RT_(f))/(1000 DeltaH_(fus))`
C. `K_(f)=(RT_(f)^(2))/(1000 L_(fus))`
D. `K_(f)=T_(b)^(2)/(1000 L_(vap))`

Answer

3

Explanation

Here `R` is universal gas constant, `T_(f)` is the normal freezing point of pure solvent and `L_(fus)` is the latent heat of fusion per gram of solvent `(DeltaH_(fus)//Molar mass)`.