According to Raoult's law, relative lowering of vopour pressure of a solvent is equal to

Options

A. moles of solute
B. mole fraction of solute
C. moles of solvent
D. mole fraction of solvent

Answer

2

Explanation

according to second Raoult's law, the relative lowering of vapour pressure of a volatile solvent containing a non-volatile solute is equal to the mole fraction of the solute in the solution.
`(P_(1)^(0)-P^(0))/P_(1)^(0) X_(2)=n_(2)/(n_(1)+n_(2))`