The volume strength of `1.5 N H_2O_2` solution is

Options

A. `8.4`
B. `4.8`
C. `8.8`
D. `5.2`

Answer

1

Explanation

Volume strength of `H_(2)O_(2)` solution is related to its volume strength as follows:
`V =5.6 N`
`=(5.6)(1.5)`
`=8.4`
Alternatively
Strength `H_(2)O_(2) =("Normality")("Gram equivalent mass")`
`=(1.5 eq L^(-1))(17 g eq^(-1))`
`=25.5 g L^(-1)`
`2H_(2)O_(2) rarr 2H_(2)O+O_(2)`
`68 g 22.4 L (at NTP)`
According to above equation
`68 g` of `H_(2)O` release `22.4 L` of `O_(2)`.
Thus, `25.5 g H_(2)O_(2) ("dissolved per "L)` will release
`22.4/68xx25.5 L O_(2)`
`=8.4 L`