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If C = molar concentration (mol L^(-1)) ...

If `C =` molar concentration `(mol L^(-1))`
`d =` density of solution `(Kg L^(-1))`
`chi_(solute)` = mole fraction of solute
`M_(solute)` = molar mass of solute in `g mol^(-1)`
`M_(solvent)` = molar mass of solvent in `g mol^(-1)`
then

A

`chi_(solute)=(CM_(solv))/(C(M_(solv)+M_(solute))+1000 d)`

B

`chi_(solute)=(CM_(solv))/(C(M_(solv)-M_(solute))+1000 d)`

C

`chi_(solute)=(CM_(solv)xx1000d)/(C(M_(solv)-M_(solute)))`

D

`chi_(solute)=(CM_(solv))/(C(M_(solv)+M_(solute))+1000 d)`

Text Solution

Verified by Experts

The correct Answer is:
2

`chi_(solute)=n_(solute)/(n_(solute)+n_(solvent))`
`=(CV_(L))/(CV_(L)+m_(solv) M_(solv))`
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