What is the fraction of the solute in a `1.00` m aqueous solution ?

Options

A. 0.0354
B. 0.0177
C. 0.177
D. 1.77

Answer

2

Explanation

`1.00 m` (one molal) aqueous solution means that 1 mol of the solute is dissolved in every `1 kg (1000 g)` of water. Thus
`n_(solute)=1`
`nH_(2)O=m_(H_(2)O)/(mm_(H_(2)O))=(1000 g)/(18 g mol^(-1))`
`=55.6 mol`
`chi_(solute)=n_(solute)/(n_(solute)+n_(H_(2)O))`
`=(1 mol)/(1 mol+55.6 mol)`
`=0.0177`