`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:

Options

A. `0.01 M`
B. `0.001 M`
C. `0.1 M`
D. `0.02 M`

Answer

1

Explanation

`n_(urea)=(6.02xx10^(20) mol ecules)/(6.20xx10^(23) mol ecules mol^(-1))`
`=10^(-3) mol`
`M=n_(urea)/V_(mL)xx(1000 mL)/L`
`=(10^(-3) mol)/(100 mL)xx(1000 mL)/L`
`=0.01 mol L^(-1)`