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A 0.002 M aqueous solution of an ionic c...

A `0.002 M` aqueous solution of an ionic compound `[Co(NH_(3))_(5)(NO_(2))] Cl` freezes at `-0.00732^(@)C`. Find the number of moles of ions which `1` mole of ionic compound produces of being dissolved in water. `(K_(f) = -1.86^(@)C//m)`.

A

`3`

B

`4`

C

`1`

D

`2`

Text Solution

Verified by Experts

The correct Answer is:
4

To find the number of moles of ions which 1 mol of ionic compound produces on being dissolved in water, we must calculate the valve of van't hoff factor (i). We have
`DeltaT_(f)=iK_(f)m`
or `i=(DeltaT_(f))/(K_(f)m)`
`=((0.00732^(@)C))/((1.86^(@)C//m)(0.0020 m))`
`=1.968`
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0.002m aqueous solution of an ionic compound Co(NH_(3))_(5)(NO_(2))CI freezes at -0.00732^(@)C .Number of moles of ions which 1 mole of ionic compound produces in water will be (K_(f) = 1.86^(@)C//m)

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