Molarity of liquid HCl with density equal to `1.17 g//mL` is:

Options

A. `36.5`
B. `18.25`
C. `32.05`
D. `42.10`

Answer

3

Explanation

`Density=(mass)/(volume)=1.17 g//c c`
This implies that in every `1 c c` there is `1.17 g HCl`. Thus, mass of `HCl` in `1000 c c (1000 mL or 1 L)` will be `1170 g`.
`n_(HCl)=(mass_(HCl))/(mm_(HCl))`
`=(1170 g)/(36.5 g mol^(-1))=32.05 mol`
`M_(HCl)=n_(HCl)/V_(mL)xx(1000 mL)/L`
`=(32.05 mol)/(1000 mL)xx(1000 mL)/L`
`=32.05 M`