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The reduction of a metal oxide if the ...

The reduction of a metal oxide if the metals formed is in ___state at the temperature of readuction

A

solid

B

liquid

C

gascous

D

Both (2) and (3)

Text Solution

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The correct Answer is:
d
The entrogy change`(Delta_(r)S^(Ө))` is higher if the metal is in liquid state or gausous state than it is in solid state .The value of energy change `(Delta S)` of the reduction process or gasous state and the metal oxide being reduced is in solid state Conspenntly ,the value of `Delta _(r)G^(Ө)` because more on begative ride and the reduction becomes easier.
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Why is the reduction of a metal oxide easier if the metal formed is in liquid state at the temperature of reduction?

Assertion : Reduction of a metal oxide is easier if the metal formed is in liquid state at the temperature of reduction. Reason : Ihe entropy is higher if the metal is in liquid state.

Statement-1: The reduction of a metal oxide is easier if the metal formed is in liquid state at he temperature of reduction. Statement-2: The value of entropy change DeltaS of the reduction process is more on +ve side when the metal formed is in liquid state and the metal oxide being reduced in a solid state. Thus, the value of the DeltaG becomes more or negative side.