If A=5 units,B= 6 units and `|vec(A)xxvec(B)|= 15 units`, then what is the angle between `vec(A)` and `vec(B)`?

If vec(A)xxvec(B)=vec(B)xxvec(A) , then the angle between vec(A) and vec(B) is-

If vec(A)xxvec(B)=vec(B)xxvec(A) , then the angle between vec(A) and vec(B) is-

If vec(A)xxvec(B)=vec(B)xxvec(A) , then the angle between vec(A) and vec(B) is-

If vec(A)xxvec(B)=vec(B)xxvec(A) , then the angle between vec(A) and vec(B) is-

If vectors vec(A),vec(B) and vec(C) have magnitudes 8,15 and 17 units and vec(A) +vec(B) = vec(C) , find the angle between vec(A) and vec(B) .

If vec(A)=vec(B)+vec(C ) , and the magnitudes of vec(A) , vec(B) , vec(C ) are 5,4, and 3 units, then the angle between vec(A) and vec(C ) is

If vec(A)=vec(B)+vec(C ) , and the magnitudes of vec(A) , vec(B) , vec(C ) are 5,4, and 3 units, then the angle between vec(A) and vec(C ) is