Which of the following orders is incorret?

Options

A. `H_(2)O gt H_(2)S gt H_(2)Se gt H_(2)Te` (thermal stability)
B. `H_(2)Olt H_(2)S lt H_(2)Se lt H_(2)Te` (acidic stability)
C. `H_(2)Te gt H_(2)O gt H_(2)S gt H_(2)Se` (boiling point)
D. `H_(2)O gt H_(2)S gt H_(2)Se gt H_(2)Te` (dipole stability)

Answer

3

Explanation

Correct order of nitrogen dioxide point is
`H_(2)O(373 K) gt H_(2)Te (269K) gt H_(2)Se(232K) gt H_(2)S(213K)`
Water has the hightedt boiling point on account of strong intermolecular H-bonding. Thus order of volatility is
`H_(2)O lt H_(2)Te lt H_(2)S lt H_(2)S`.
Acidic character of the hydrides increases from `H_(2)O` to `H_(2)Te`. The increase in acidic character can be explained in terms of decrease in bond `(H-E)` dissociation enthalpy down the group.
Owing to the decrease in ond `(H-E)` dissocaition enthalpy down the group,the thermal stability of hydrides also decreases from `H_(2)O` to `H_(2)Te`. All the hydride except water possess reducing property and this character increases from `H_(2)S` to `H_(2)Te`