The hybridization of atomic orbitals of nitrogen is `NO_(2)^(+), NO_(3)^(-)`, and `NH_(4)^(+)` respectively are

Options

A. `sp, sp^(3)` and `sp^(2)`
B. `sp^(2), sp^(3)` and `sp`
C. `sp, sp^(2)` and `sp^(3)`
D. `sp^(2), sp` and `sp^(3)`

Answer

3

Explanation

`NO_(2)^(+)implies` [steric number=`2`atoms +`0` lone pair]`implies` sp hybridisation
Or number of hybrid orbitals `(x)implies(1)/(2)[Ve+MA-c+a]`
`implies(1)/(2)[5+0-1+0]implies2implies sp` hybridization
`NO_(3)^(-)implies` [steric number=`3`atoms +`0`lone pair]
`impliessp^(2)` hybridisation
`NH_(4)^(+)implies` [ateric number =`4`atoms+`0`lone pair]
`impliessp^(2)` hybridisation