The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)^(2-)`, and `S_(2)O_(6)^(2-)` follow the order

Options

A. `S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-) lt SO_(3)^(2-)`
B. `S_(2)O_(6)^(2-) lt S_(2)O_(4)^(2-) lt SO_(3)^(2-)`
C. `S_(2)O_(4)^(2-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`
D. `SO_(3)^(2-) lt S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-)`

Answer

2

Explanation

Oxiation state of `S`in `S_(2)O_(3)^(2-)`
`x+(3)(-2)=-2`
` x=+4`
Oxidation states fo `S` in `S_(2)O_(4)^(2-)`
` 2x+4(-2)=-2`
` 2x=+6`
`x=+3`
Oxidation state of S in`S_(2)O_(6)^(2-)`
`2x+6(-2)=-2`
`2x=10`
`x=+5`