`Zn` gives `H_(2)` gas with `H_(2)SO_(4)` and `HCl` but not with `HNO_(3)` because

Options

A. `Zn` acts a oxidies agent where it reacts with `HNO_(3)`
B. `HNO_(3)` is a weaker acid than `H_(2)SO_(4)` and `HCl`
C. `Zn ` is placed above hydrogen in electrochemical series.
D. `NO_(3)^(-)` is reduced in preference to hydronium ion

Answer

3

Explanation

`Zn` liberates `H_(2)` gas from dilute `HCl//H_(2)SO_(4)` as it is presetn aboce `H` in electrochemical series
`[E_(Zn^(2+)//Zn)^(Ɵ) lt E_(H^(+)//H_(2))]`
But `HNO_(3)` is an oxidising agent thus hydrogen gas released initially gets oxidized to `H_(2)` ol while `NO_(3^(-)` is reduced :
` Zn +2HNO_(3)rarr Zn(NO_(3))_(2)+2H]xx4`
`(~60%)`
`{:(HNO_(3)+8H rarr NH_(3)+3H_(2)O),(NH_(3)+HNO_(3) rarr NH_(4)NO_(3)),(bar(4Zn+10HNO_(3) rarr 4Zn(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O)):}`