The equilibrium constant is `10` at `100 K`. Hence, `DeltaG` will be negative.

Equilibrium constant, K changes with temperature. At 300K, equilibrium constant is 25 and at 400K it is 10. Hence, backward reaction will have energy of activation

The equilibrium constant for a reaction is 10 . What will be the value of DeltaG^(Θ) ? R=8.314 J K^(-1) mol^(-1), T=300 K .

The equilibrium constant for a reaction is 10 . What will be the value of DeltaG^(Θ) ? R=8.314 J K^(-1) mol^(-1), T=300 K .

The equilibrium constant for a reaction is 10. What will be the value of DeltaG^theta at 300 K

The equilibrium constant of a reaction is 10, what will be the sign of DeltaG ? Will this reaction be the sign of DeltaG ? Will this reaction be spontaneous ?

The equilibrium constant for a reaction is 10. What will be the value of DeltaG^@ ? R = 8.314 J K^(-1) mol^(-1), T = 300K.