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If (cosx)^y = (siny)^x, then (dy)/(dx) ...

If `(cosx)^y = (siny)^x`, then `(dy)/(dx)` equals-

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If (cosx)^y=(siny)^x , find (dy)/(dx)

If (cosx)^(y)=(siny)^(x), then find (dy)/(dx) .

Knowledge Check

  • If y^(cosx)=x^(siny)," then "(dy)/(dx)=

    A
    `(y(xsinxlogy+siny))/(x(cosx-ylogxcosy))`
    B
    `(y(xsinxlogx-siny))/(x(cosx+ylogxcosy))`
    C
    `(y(siny-xlogy))/(x(x-ycosy(logx)))`
    D
    `(y(siny+xlogy))/(x(x+ycosy(logx)))`

  • If y=log_(cosx)sinx, then (dy)/(dx) is equal to

    A
    `(cotxlogcosx+tanxlogsinx)/(logcosx)^(2)`
    B
    `(tanxlogcosx+cotxlogsinx)/(logcosx)^(2)`
    C
    `(cotxlogcosx+tanxlogsinx)/(logsinx)^(2)`
    D
    none of these

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    Explore conceptually related problems

    If (cosx)^(y)=(siny)^(x), then find (dy)/(dx) .

    If (cosx)^(y)=(siny)^(x), then find (dy)/(dx) .

    If (cosx)^y=(siny)^x , find (dy)/(dx) .

    If (cosx)^(y)=(siny)^(x), then find (dy)/(dx) .

    If (cosx)^(y)=(siny)^(x), then find (dy)/(dx) .

    If y=log_(cosx)sinx, then (dy)/(dx) is equal to

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