The sum of roots of `1/(x+a)+1/(x+b)=1/c` is zero, the product of the roots is:

The sum of roots of equation 1/(x+a)+1/(x+b)=1/c is zero find the product of roots of equation a)0 b) ((a+b)/2) c) -((a^2+b^2)/2) d) 2(a^2+b^2)

If the sum of the roots of equation (1)/(x+a)+(1)/(x+b)=1/c is zero, then the product of roots is :

The sum of the roots of the equation 1/(x+a) + 1/(x+b) = 1/c is zero. What is the product of the roots of the equation ?

The sum of the roots of 6x^2 = 1 is

The sum of roots of equation (1)/(x+a)+(1)/(x+b)=(1)/(c) is zero find the product of roots of equation a)0b ) ((a+b)/(2))c)-((a^(2)+b^(2))/(2))d(a^(2)+b^(2))

If the sum of roots of the equation (1)/(x+a)+(1)/(x+b)=(1)/(c ) is zero, prove that product of the roots is -(a^(2)+b^(2))/(2)

If the sum of the roots of the equation 1/(x+a)+1/(x+b)=1//c is zero, the prove that the product of the root is (-1/2)(a^2+b^2)dot

If the sum of the roots of the equation 1/(x+a)+1/(x+b)=1//c is zero, the prove that the product of the root is (-1/2)(a^2+b^2)dot

If the sum of the roots of the equation 1/(x+a)+1/(x+b)=1//c is zero, the prove that the product of the root is (-1/2)(a^2+b^2)dot

If the sum of the roots of the quadratic equation is 1/(x+p)+1/(x+q)=1/r is zero,show that the product of the roots is -((p^2+q^2)/2) .