A string of length 1.5 m with its two ends clamped is vibrating in fundamental mode. Amplitude at the centre of the string is 4 mm. Minimum distance between the two points having amplitude 2 mm is:

A string of length 1 . 5 m with its two ends calmped is vibrating in fundamental mode. Amplitude at the centre of the string is 4 mm . Find the distance between the two points (in m) having amplitude 2 mm .

A string of mass per unit length mu is clamped at both ends such that one end of the string is at x = 0 and the other is at x =l . When string vibrates in fundamental mode, amplitude of the midpoint O of the string is a, tension in a, tension in the string is T and amplitude of vibration is A. Find the total oscillation energy stored in the string.

A string of mass per unit length mu is clamped at both ends such that one end of the string is at x = 0 and the other is at x =l . When string vibrates in fundamental mode, amplitude of the midpoint O of the string is a, tension in a, tension in the string is T and amplitude of vibration is A. Find the total oscillation energy stored in the string.

A string of mass per unit length mu is clamped at both ends such that one end of the string is at x = 0 and the other is at x =l . When string vibrates in fundamental mode, amplitude of the midpoint O of the string is a, tension in a, tension in the string is T and amplitude of vibration is A. Find the total oscillation energy stored in the string.

A string of mass 'm' and length l , fixed at both ends is vibrating in its fundamental mode. The maximum amplitude is 'a' and the tension in the string is 'T' . If the energy of vibrations of the string is (pi^(2)a^(2)T)/(etaL) . Find eta

A string of mass 'm' and length l , fixed at both ends is vibrating in its fundamental mode. The maximum amplitude is 'a' and the tension in the string is 'T' . If the energy of vibrations of the string is (pi^(2)a^(2)T)/(etaL) . Find eta

A string of mass 'm' and length l , fixed at both ends is vibrating in its fundamental mode. The maximum amplitude is 'a' and the tension in the string is 'T' . If the energy of vibrations of the string is (pi^(2)a^(2)T)/(etaL) . Find eta

A string of length l is fixed at both ends and is vibrating in second harmonic. The amplitude at anti-node is 5 mm. The amplitude of a particle at distance l//8 from the fixed end is

A string of length l is fixed at both ends and is vibrating in second harmonic. The amplitude at anti-node is 2 mm. The amplitude of a particle at distance l//8 from the fixed end is