A particle is moving rectilineraly so that its acceleration is given as `a = 3t^(2) + 1 m//s^(2)`. Its initial velocity is zero.

A particle moves along a straight line in such a way that its acceleration is increasing at the rate of 2 m//s^(3) . Its initial acceleration and velocity were zero. Then, the distance which it will cover in the 3^(rd) second (t=2 " to "t =3 " sec") is :

A particle is moving on a straight line with constant retardation of 1 m//s^(2) . Its initial velocity is 10 m//s .

A particle is moving in such a way that its displacement s at the t is given by s=2t^(2)+5t+20. After 2 seconds its velocity is

A particle is moving in a straight line. Its displacement at time t is given by s(I n m)=4t^(2)+2t , then its velocity and acceleration at time t=(1)/(2) second are

A particle is moving in a straight line. Its displacement at time t is given by s(I n m)=4t^(2)+2t , then its velocity and acceleration at time t=(1)/(2) second are

A particle in moving in a straight line such that its velocity is given by v=12t-3t^(2) , where v is in m//s and t is in seconds. If at =0, the particle is at the origin, find the velocity at t=3 s .

A particle is moving under a constant acceleration of 3m//s^(2) . The initial velocity of the particle is 10m/s. calculate the distance travelled by the particle is 5s and also in th 5th second of its motion.

A particle is moving along a circle of radius 3 m .If its centripetal acceleration is 3ms^(-2) , its angular velocity in rad s^(-1) is

The displacement of a particle moving along a straight line is given by s=3t^(3)+2t^(2)-10t. find initial velocity and acceleration of particle.