" (i) "(2sqrt(6)-sqrt(5))/(3sqrt(5)-2sqrt(6))

Rationales the denominator and simplify: (sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2)) (ii) (5+2sqrt(3))/(7+4sqrt(3)) (iii) (1+sqrt(2))/(3-2sqrt(2)) (2sqrt(6)-sqrt(5))/(3sqrt(5)-2sqrt(6)) (v) (4sqrt(3)+5sqrt(2))/(sqrt(48)+sqrt(18)) (vi) (2sqrt(3)-sqrt(5))/(2sqrt(3)+3sqrt(3))

(sqrt(6)+sqrt(3))/(sqrt(5)+sqrt(2))

Simplify each of the following by rationalising the denominator,(1)/(5+sqrt(2)) (ii) (5+sqrt(6))/(5-sqrt(6)) (iii) (7+3sqrt(5))/(7-3sqrt(5)) (iv) (2sqrt(3)-sqrt(5))/(2sqrt(2)+3sqrt(3))

Simplify each of the following by rationalising the denominator; 1/(5+sqrt(2)) (ii) (5+sqrt(6))/(5-sqrt(6)) (iii) (7+3sqrt(5))/(7-3sqrt(5)) (iv) (2sqrt(3)-sqrt(5))/(2sqrt(2)+3sqrt(3))

(sqrt(6+2sqrt(5)))(sqrt(6-2sqrt(5)))

Rationalise the denominator and simplify (2sqrt6-sqrt5)/(3sqrt5-2sqrt6)

Rationalize the denominator and simplify: (2sqrt6-sqrt5)/( 3sqrt5-2sqrt6)

(sqrt(6)+sqrt(5)+ 1/(sqrt(6)+sqrt(5)))^2

If (6)/(2sqrt(3)-sqrt(5))=(12sqrt(3)+6sqrt(5))/(k), then k=