Let `f: R^+ ->R` be a function which satisfies `f(x)dotf(y)=f(x y)+2(1/x+1/y+1)` for `x , y > 0.` Then find `f(x)dot`

Let f:R^(+)rarr R be a function which satisfies f(x)f(y)=f(xy)+2((1)/(x)+(1)/(y)+1) for x,y>0. Then find f(x)

Let f:R->R be a function such that f(x+y)=f(x)+f(y),AA x, y in R.

Let f:R->R be a function such that f(x+y)=f(x)+f(y),AA x, y in R.

Let f be a differentiable function satisfying f(x/y)=f(x)-f(y) for all x ,\ y > 0. If f^(prime)(1)=1 then find f(x)dot

Let f be differentiable function satisfying f((x)/(y))=f(x) - f(y)"for all" x, y gt 0 . If f'(1) = 1, then f(x) is

Let f be differentiable function satisfying f((x)/(y))=f(x) - f(y)"for all" x, y gt 0 . If f'(1) = 1, then f(x) is

Let f be differentiable function satisfying f((x)/(y))=f(x) - f(y)"for all" x, y gt 0 . If f'(1) = 1, then f(x) is

Let f be differentiable function satisfying f((x)/(y))=f(x) - f(y)"for all" x, y gt 0 . If f'(1) = 1, then f(x) is

A continuous function f(x)onR->R satisfies the relation f(x)+f(2x+y)+5x y=f(3x-y)+2x^2+1forAAx ,y in R Then find f(x)dot

A continuous function f(x)onR->R satisfies the relation f(x)+f(2x+y)+5x y=f(3x-y)+2x^2+1forAAx ,y in R Then find f(x)dot