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[" Q."int(22)^(5)5^(5^(x))*5^(5^(x))*5^(...

[" Q."int_(22)^(5)5^(5^(x))*5^(5^(x))*5^(x)dx=]

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int5^(5^(5^(x)))*5^(5^(x))*5^(x)dx

int5^(5^(5^(x)))*5^(5^(x))*5^(x)*dx

int 5^(5^(5^(x)))*5^(5^(x))*5^(x)dx=

int 5^(5^(5^x))*5^(5^x)*5^x *dx

int5^(5^(5^(x)))*5^(5^(x))*5^(x)backslash dx

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int5^(5^(x^(2)))*5^(5^(x))*5^(x)backslash dx is equal to

int_(0)^(5)x(5-x)^(10)dx=