[" At a certain temperature,only "50%HI" is "],[" dissociated into "H_(2)" and "I_(2)" at equilibrium.The "],[" equilibrium constant is: "]

At certain temperature 50% of HI is dissociated into H_(2) and I_(2) the equilibrium constant is

At a certain temperature , 2HI ⇌ H_2 + I_2 on 50 % HI is dissolved at equilibrium .What the value of equilibrium constant ?

At a certain temp. 2HI hArrH_(2) + I_(2) . Only 50% HI is dissociated at equilibrium. The equilibrium constant is

At a certain temp. 2HI hArrH_(2) + I_(2) . Only 50% HI is dissociated at equilibrium. The equilibrium constant is

At a certain temperature , only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g)hArrH_(2)(g)+I_(2)(g) the equilibrium constant for this reaction is:

At a certain temperature , only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g)hArrH_(2)(g)+I_(2)(g) the equilibrium constant for this reaction is:

At a certain temperature , only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g)hArrH_(2)(g)+I_(2)(g) the equilibrium constant for this reaction is:

When 2.00 mol each of H_2(g) and I_2(g) are reacted in a 1.00 L container at a certain temperature , 3.50 mol of HI is present at equilibrium.Calculate the value of the equilibrium constant , K_c for the reaction : H_2+I_2hArr 2HI