" For what value of "n,2^(n)times5^(n)" ends with "5?

For what value of n,2^(n)xx5^(n) ends in 5

If m, n are natural numbers, for what values of m, does 2^(n)times5^(m) ends in 5?

For what value of n ,\ 2^nxx5^n ends in 5.

For any 'n', 6^(n) - 5^(n) ends with

For what values of n is 14^(n)+11^(n) divisiblle by 5 ?

show that there is no value of n for which ( 2^(n) xx 5 ^(n)) ends in 5.

If n is any natural number, then 9^(n)-5^(n) ends with

If n is any natural number,then 6^(n)-5^(n) always ends with (a) 1 (b) 3 (c) 5 (d) 7 [Hint: For any n in N,6^(n) and 5^(n) end with 6 and 5 respectively.Therefore,6^(n)-5^(n) always ends with 6-5=1.

The value of 2^(n)n!(1.3.5.....(2n-1)) is

For all values of n . N ( n+1) (n+5) will be divisible by