The length of the perpendicular from the origin to the line `(x sin alpha )/(b)-(y cos alpha )/(a)-1=0` is

The length of the perpendicular from the origin on the line (x sin alpha)/(b ) - (y cos alpha)/(a )-1=0 is

The length of perpendicular from the origin on the line x/a + y/b = 1 is -

If p and q are the lengths of the perpendiculars from the origin to the straight lines x "sec" alpha + y " cosec" alpha = a " and " x "cos" alpha-y " sin" alpha = a "cos" 2alpha, " then prove that 4p^(2) + q^(2) = a^(2).

If p and q are the lengths of the perpendiculars from the origin to the straight lines x sec alpha+y cosec alpha=a and x cos alpha-y sin alpha=a cos 2alpha, prove that 4p^(2)+q^(2)=a^(2)

If P_(1) and p_(2) are the lenghts of the perpendiculars drawn from the origin to the two lines x sec alpha +y . Cosec alpha =2a and x. cos alpha +y. sin alpha =a. cos 2 alpha , show that P_(1)^(2)+P_(2)^(2) is constant for all values of alpha .

If p be the length of the perpendicular from the origin on the line x/a+y/b=1 , then

The perpendicular distance from origin to the line x/(p sec alpha)+y/(p cosec alpha)=1 is

The foot of the perpendicular from (0, 0) to the line x cos alpha+y sin alpha=p is

The foot of the perpendicular from (0,0) to the line x cos alpha+y sin alpha=p is