t=r sin theta cos phi,y=r sin theta

If x=r sin theta cos phi,y=r sin theta sin phi and z=r cos theta,thenx^(2)+y^(2)+ is independent of theta,phi(b)r,theta(c)r,phi(d)r

If x=r sin theta cos phi, y= r sin theta sin phi, z=r cos theta , prove that x^2+y^2+z^2=r^2 .

If x= r sin theta cos phi , y=rsin theta sin phi and z=r costheta then the value of sqrt(x^2+y^2+z^2) will be

If x=r cos theta cos phi, y=r cos theta sin phi, z=r sin theta , then prove that x^(2)+y^(2)+z^(2)=r^(2).

If x=r cos theta cos phi , y=r cos theta sin phi and z=r sin theta , then x^(2)+y^(2)+z^(2)=

If x=gamma sin theta cos phi, y=gamma sin theta sin phi, z =gamma cos theta , what is the eliminant of theta and phi ?

If x = r cos theta cos phi, y = r cos theta sin phiz = r sin theta, then x ^ (2) + y ^ (2) + z ^ (2) = (i) r ^ (2) (ii ) y ^ (2) (iii) x ^ (2) (iv) z ^ (2)

The product of matrices A = [(cos^(2) theta, cos theta sin theta),(cos theta sin theta , sin^(2) theta)] and sin B = [(cos^(2)phi, cos phi sin phi),(cos phi sin phi, sin^(2) phi)] is a null matrix if theta - phi =

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi),(cos phi sin phi,sin^2 phi)]=0