[" Two bodies of masses "m_(1)" and "m_(2)" are initially at "],[" rest placed infinite distance apart.They are then "],[" allowed to move towards each other under "],[" mutual gravitational attraction.Their relative "],[" velocity when they are "r" distance apart is - "]

Two bodies of mass m_(1) and m_(2) are initially at rest placed infinite distance apart. They are then allowed to move towards each other under mutual gravitational attaction. Show that their relative velocity of approach at separation r betweeen them is v=sqrt(2G(m_(1)+m_(2)))/(r)

Two bodies of mass m_(1) and m_(2) are initially at rest placed infinite distance apart. They are then allowed to move towards each other under mutual gravitational attaction. Show that their relative velocity of approach at separation r betweeen them is v=sqrt(2G(m_(1)+m_(2)))/(r)

Two bodies of masses m_1 and m_2 initially at rest at infinite distance apart move towards each other under gravitational force of attraction. Their relative velocity of approach when they are separated by a distance r is (G= universal gravitational constant.)

Two particles of masses m_(1) and m_(2) are intially at rest at an infinite distance apart. If they approach each other under their mutual interaction given by F=-(K)/(r^(2)) . Their speed of approach at the instant when they are at a distance d apart is

Two particles of masses m_(1) and m_(2) are intially at rest at an infinite distance apart. If they approach each other under their mutual interaction given by F=-(K)/(r^(2)) . Their speed of approach at the instant when they are at a distance d apart is