" x satisfies all the conditions of Rolle's theorem in "[-3,0]" .The value of "c" is "

The function f(x) = x(x+3)e^(-x/2) satisfies all the conditions of Rolle's theorem in [-3,0]. The value of c is

The function f(x)=x(x+3)e^(-(1/2)x) satisfies the conditions of Rolle's theorem in (-3,0). The value of c, is

The function f(x)=x(x+3)e^(-(1/2)x) satisfies the conditions of Rolle's theorem in (-3,0). The value of c, is

The function f(x)=x(x+3)e^(-(1/2)x) satisfies the conditions of Rolle's theorem in (-3,0). The value of c, is

The function f(x) = x(x+3) e^(-x/2) satisfies all the conditions of Rolle's theorem on (-3,0) . Find the value of c such that f'(c) = 0

If the function f(x)= e^x(sinx-cosx), x in [(pi)/4, (5pi)/4] satisfies all the conditions of the Rolle's theorem, then the value of c is...... A) 0 B) pi C) pi/2 D) pi/4

The function f(x)=x^(3)-6x^(2)+ax+b satisfy the conditions of Rolle's theorem in [1,3] .The values of a and b are

If the function f(x)=4x^(3)+ax^(2)+bx-1 satisfies all the conditions of Rolle's theorem in -(1)/(4) le x le 1 and if f'((1)/(2))=0 , then the values of a and b are -