यदि `(1-ix)/(1+ix) =a -ib` , a का मान है

If a,b, xin R and if (1-ix)/(1+ix)=a-ib ,prove that a^2 + b^2 = 1 .

sinh ix =

if (1-ix)/(1+ix)=a-ib ,then prove that a^2+b^2=1 (a,b x are real).

Show that a real value of x will satisfy the equation (1-ix)/(1+ix)= a -ib if a^2+b^2=1 , where a, b are real.

If a,b are real and a^(2)+b^(2)=1, then show that, the equation (1-ix)/(1+ix)=a-ib is satisfied by a real value of x.

The relation between the real numbers a and b ,which satisfy the equation (1-ix)/(1+ix)=a-ib, for some real value of x, is

Sinh (ix) =

If a,b, x in R and (1-ix)/(1+ix)=a+ib ,then prove that a^2+b^2=1

If a,b are real and a^2+b^2=1 ,then prove that the equation. (1-ix)/(1+ix)=a-ib is satisfied for all real values of x.

If A =(x-1)/(x+1) then, the value of A-1/A is: यदि A =(x-1)/(x+1) तो A-1/A का मान: