A particle stats from rest at the origin with a constant acceleration

Calculate the position of the particle at `t=5 ` second.

A particle starts from rest and moves with constant acceleration. Then velocity displacement curve is:

A particle starts from rest and moves with constant acceleration. Then velocity displacement curve is:

A particle, starting from rest, moves with constant acceleration 4 ms^(-2). The distance travelled by the particle in 5^(th) second is.

A particle is initially at rest. It starts moving with a constant acceleration, the speed of the particle in t seconds is 50m/s and after one second the speed becomes 75m/s. calculate the acceleration of the particle and distance covered in (t+1)^("th") second of its motion.

A particle is kept at rest at the origin. A constant force rarrF starts acting on it at t = 0 . Find the speed of the particle at time t.

A particle is kept at rest at the origin. A constant force rarrF starts acting on it at t = 0 . Find the speed of the particle at time t.

A particle starts from rest at the origin and moves along the positive x direction. Its acceleration a versus position x graph is shown in the figure. The velocity of the particle at x = 6 m is?

A particle starts from rest and travels with constant acceleration 'a' . After a time of 't_(0)' it 's acceleration direction gets reversed . Identify correct options.

A particle starts from rest with uniform acceleration a . Its velocity after n seconds is v . The displacement of the particle in the two seconds is :