Find the equation of trajectory of a particle whose velocity components are
`v_(x)=2x+1, v_(y)=2y+3`
Given that particle starts from rest from origin.

The motion of a particle along straight line is given by v^(2) = u^(2) + 90s . If the particle starts from rest, then the acceleration is

Velocity of a particle varies with time as v=athati+2ht^(2)hatj . If the particle starts from point (0,c) , the trajectory of the particle is

Velocity of a particle varies with time as v=athati+2ht^(2)hatj . If the particle starts from point (0,c) , the trajectory of the particle is

Instantaneous velocity of a particle moving in +x direction is given as v = (3)/(x^(2) + 2) . At t = 0 , particle starts from origin. Find the average velocity of the particle between the two points p (x = 2) and Q (x = 4) of its motion path.

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

Starting from rest, the acceleration of a particle is a=2(t-1) . The velocity (i.e. v=int" a dt " ) of the particle at t=10 s is :-

Starting from rest, the acceleration of a particle is a=2(t-1) . The velocity (i.e. v=int" a dt " ) of the particle at t=10 s is :-

Starting from rest, the acceleration of a particle is a=2(t-1) . The velocity (i.e. v=int" a dt " ) of the particle at t=10 s is :-